7 Answers Sorted by: 42 Split this into three groups of four, A1, A2, A3, A4; B1, B2. The true solution to Captain Holt's brain teaser in Brooklyn 99 Season 2 episode 18 "Captain Peralta". Can someone suggest how we can modify the answer above ? Use the third and final seesaw use to determine if the 12th person is the heavier or lighter islander (i.e. There was a problem preparing your codespace, please try again. L: sit on the left, R: sit on the right, -: don't sit on the seesaw.. Feel free to provide your own comment and I can delete this one. " If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. You must figure out which. Number the men 1,2,312. If they are equal, it is the remaining man not being measured. Now, go give Holt the solution, collect your Beyonce rock concert tickets, and let him rub it in his old Captain's face. I like Rosa's answer squeeze until fatty confesses. I am just looking for a little tweak to this answer. Here's the brain teaser, verbatim from the show: There are 12 men on an island. The first measurement of 4 vs. 4 was equal. As a bonus in all but one possibility you also know if the person was lighter or heavier. The seesaw will NOT be perfectly balanced. 11 weigh exactly the same, but one of them is slightly lighter or heavier. The riddle, as you'll recall, is this: There are twelve men on an island. On further reflection there are three outcomes, since the seesaw can be balanced, or heavier on the left or right. If the 9,10,11 differs from 1,2,3, then weigh 9 against 10. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. If the see saw is not balanced, remove one from each end. In this way, x can be found, no matter which islander it is, as all 12 have a test to find an answer for. now compare R2 and R3. A standard see-saw must be used and only three times. If the seesaw reverses, ether 4 or 5 is the oddly weighted one. If they are the same, 7 is different (and lighter). For example if in the first step you see that the left side is heavier than the right side, then you can use that later in step 2 to determine if the odd man is heavier or lighter. There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows . 1 v 12). SPOILER ALERT! (Third Use), If the see saw is not balanced, remove one from each end. How do you do it? Was Galileo expecting to see so many stars? Note : I am not looking for a new way to solve this. Weapon damage assessment, or What hell have I unleashed? Work fast with our official CLI. Example for condition 1: put three "unknowns" against three "knowns". Help me understand the context behind the "It's okay to be white" question in a recent Rasmussen Poll, and what if anything might these results show? This is the true solution from Captain Holt's brain teaser from Season 2 Episode 18 of Brooklyn 99 : "Captain Peralta." we now know that the odd islander is S4. ", (Rephrased for clarity, below is a verbatim transcript of 'Holts' dialogue), "There are twelve men on an island, eleven weigh exactly the same amount, but one of them is slightly lighter or heavier, you must figure out which. The seesaw itself is a lever. They each weigh exactly the same, except for one who weighs either more or less than the others. Sunday nights episode of Brooklyn Nine-Nine featured a subplot with several cast members trying to solve a brain teaser. But this is simple! Beach House Semis in Port Union Village. sideline: S1 S2 S3 S4 Otherwise the one who stayed is the oddly weighted one. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. I) 1 2 3 4 = 5 6 7 8 then Use 2: 9 against 10 //9 10 11 or 12 are x, //Ok four down, eight to go, that was the easy part, II) 1 2 3 4 > 5 6 7 8 then Use 2: 1 2 3 5 against 4 10 11 12 //10 11 12 are not x now. Now put 7 on one end and 8 on the other. (seesaw measurement number 3), 2.B.3 if right heavy All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. You have to figure out which Islander is the heaviest using a seesaw. What is the arrow notation in the start of some lines in Vim? The following steps become identical to those in Scenario 1., above. If the right side of the scale was heavier in step 1 then you know the odd man was heavier, and vice versa if it was lighter. :D, Brooklyn 99 riddle: Weighing Islanders [duplicate]. sideline: S1 R2 R3 R4, we know there is a heavy islander amongst L2 L3 L4 You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. Fun: (2.49) Difficulty: (1.28) Puzzle ID: #13528 Submitted By: cool_star. In step 3 place one unknown on each side. There are 2 possible outcomes, either they are equal, or unequal. Thanks! Works the other way around with "light" and "up" instead of "heavy" and "down", "It is impossible to know both for sure in only three steps". You signed in with another tab or window. The answer isnt TV friendly. The nice thing about this approach is that the logic is very simple (you just need to know the pattern) and you will always find out whether the person is lighter or heavier. Solution 2c. A tag already exists with the provided branch name. Please The island has no escapes, but there is a seesaw. Ackermann Function without Recursion or Stack. Are there basic weighing puzzles requiring adaptive strategies? Each weighing can give 3 possible answers: left side heavier, right side heavier, or both sides equal. (seesaw measurement number 3). 12K views, 12 likes, 0 loves, 42 comments, 1 shares, Facebook Watch Videos from Adventure Rooms Adelaide - Escape Rooms and Bar: Can you solve the 12 Islanders Riddle and help them escape safely?. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (balanced) How is "He who Remains" different from "Kang the Conqueror"? now compare L2 and L3. I gave each of the 12 men a letter, A-L. Can You Solve the Brain Teaser of the 12 Men and a See-Saw? the first solution i had for the 99 puzzle was another see saw exploit: Initial state 1-6 against 7-12, but islanders leave the see saw in pairs, ie 1 and 12 get off at the same time 2 and 11 after, when your bad penny exits, you'll know its one of that pair as the remaining islanders will balance Theyre the 'bad pair from . It is a good write up though. Learn more about Stack Overflow the company, and our products. to use Codespaces. Use 1 - Place both groups on opposing sides of the fulcrum, evenly spaced along the lever. Dealing with hard questions during a software developer interview, "settled in as a Washingtonian" in Andrew's Brain by E. L. Doctorow. You must figure out which. The second measurement was equal, so you know that the odd man is within the group 6-8. Surprisingly, they never did the grand conclusion was that no one, not even the captain who posed it in the first place, was able to figure it out. Weigh 1 against 2. Answer explained - step by step Number the islanders 1 to 12 First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. (Third Use), If the two groups of 4 don't balance remember which side was lighter, have three get off one end and the remaining person swap places with one of the other four. @Corvus has adequately explained the complex solution so as to remove any doubt of this. Each islander is given a position to sit on the seesaw for each round. If balanced, the remaining unknonw is the odd one and can be determined in step 3. Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. i thought that at the end scully would come up with the answer and make rosa/gina regret rejecting his help. now compare R1 against a neutral islander (S1 for example). All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Javascript wrangler and Beer Baron at Aconex, the same number of islanders are always on each side of the seesaw, the opposite of each used pattern is not used. Wow how did this even get 8 upvotesmind boggling. Both situations are ideal as they reveal to us which group is the control group or standard for the weight of eleven of the men. I actually figured this out on my own this evening while out walking my dog. Comparing (1,2,3,4) to (5,6,7,8) does exactly this. There are two possible results. Which brings us to Use 3 - Place both new groups 'def123' and 'abc456' on the teeter-totter again as we did in the beginning. Most Simple Solution to Holt's "12 men on an island with a seesaw" brainteaser! One of two things will happen: The seesaw will be perfectly balanced. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Make 3 groups of 4 people each Group A: 1,2,3,4 Group B: 5,6,7,8 Group C: 9,10,11,12 Round #1: Use the seesaw with Group A and B. Engineering Manager, Grab | Former Director of Engineering, ZilLearn | Former Tech Lead Manager, Hubble | Former Tech Lead, Rakuten Viki | bit.ly/weiyuan. Can a VGA monitor be connected to parallel port? The pattern for all islanders is below: person: A B C . Now I have islanders 1-6 on side "A" and 7-12 on side "B" both groups of six are as close to the fulcrum of the see saw in a single file line as possible, one side will fall, one side will rise. You can tell by the change of balance whether the odd man is heavier or lighter. Can a VGA monitor be connected to parallel port? Scenario Two, from your original 4x4 weighing: 2. The See-Saw. Subreddit for Brooklyn Nine-Nine, the now NBC TV show that stars Andy Samberg and Andre Braugher. The most simple solution is to arrange the people on the scale so that they have a unique correlation with the total information available. Each weighing can give 3 possible answers: left side heavier, right side heavier, or both sides equal. If nothing happens, download GitHub Desktop and try again. Ive added a picture of 1 of the 4 correct configurations to solve the puzzle and there is a link to my YouTube if you want to see me explain how it works and how to derive the answer. Would the reflected sun's radiation melt ice in LEO? The island has no scales but there is a see-saw. Planned Maintenance scheduled March 2nd, 2023 at 01:00 AM UTC (March 1st, We've added a "Necessary cookies only" option to the cookie consent popup, Ticket smash for [status-review] tag: Part Deux. The only case where you dont is 1.1.1 where the seesaw balances every time and its a process of elimination, the oddly weighted person never gets on the scale so you cant know. The unique and extremely popular [citation needed] authority on pop culture since 2008. put A&B on the seesaw then put A&C ( 2 uses) logic will give you the answer. Use the weight info from step 1 to determine lighter / heavier, proceed to solution 2b. 42 votes, 14 comments. You cannot determine lighter, heavier, proceed to solution 2c. Questions: (Third Use)notethis works equally well if the group was lighter, just replace terms for appropriate identification. I wonder if this is the highest-viewed duplicate question of all time? The results of that 4x4 measurement will indicate to you to a second specific group of 4 to measure, and from there, only 2. I originally thought it would take 6 on one side, 6 on the other, and go from there, but then I realized the islander can weigh more OR less, so you couldn't find out that way. Seesaw is the best interactive learning platform for PreK-5. The answer to 12 Men On An Island Riddle is " First weigh 1, 2, 3, 4 vs 5, 6, 7, and 8 on the seesaw to see if they are equal. 11 of them weigh the same and one of them is either slightly This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. You have to figure out which Islander is the heaviest using a seesaw. seesaw: L1 L2 L3 L4 R1 R2 R3 R4 You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. Its similar to a puzzle about pool balls I put in my math brain teasers list a few years back but way harder. Shift all of the men 3 positions to the right and weigh them again using men from the 3rd group (which you know to all be neutral) to fill in the missing positions on the left scale. Take 3 men from the group and measure against 3 neutral men from 1-8. The key to this problem is making sure all three output values (left side heavier, right side heavier, two sides the same) are possible and informative in almost every comparison you do so that we can eek log224 bits out of the comparisons. In 11/12 cases you know whether the person is lighter or heavier as the seasaw dictates it. (Detailed . Have something to tell us about this article? Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. sideline: S4 L1 L2 L3 L4 R4 If they are equal then. - GitHub - hellgrenj/12-islanders: Me and my wife sat down to try and s. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. The riddle: There are 12 islanders on an island. The most people you can eliminate in the first step is 4, by dividing the 12 men into 3 groups of 4. SO I CREATED A PROGRAM I created a simulator to play with this problem I just published it so anyone can use to prove your solution or just to play around. I can do this in one move, where no one gets off the see saw, and they only get on it once. Now you know that one of the four men on one side is light. Say as example 1234 were lighter. [9, 10, 11] VS. [1, 2, 3]. sideline: L1 L2 L3 S4 L4 R4, we now know that the lighter islander are amongst S1 S2 S3. So in principle, we should be able to solve the problem. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. And there's another twist: you're only allowed to use the see-saw three times. There are no scales or other weighing device on the island. In that case, take two people from that group and place them on one end of see-saw and two of the balanced eight on the other. Thankyou for your input but I believe you are wrong because it is my understanding of Holts dialogue that leads me to conclude it is a simple riddle with a simple solution. There is a seesaw to determine who is the odd one out. Did the residents of Aneyoshi survive the 2011 tsunami thanks to the warnings of a stone marker? All of these men weigh exactly In that case, take two people from that group and place them on one end of see-saw and two of the balanced eight on the other. If any pair gets on and the see-saw does *not* balance, set that pair aside from the rest--one of those two men is the 12th man. That's not true. Similar logic will help us design all further comparisons. If these are equal, the different man is 12. Weigh the lighter of the 2 men against any other neutral man. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. Take note of whether it is heavier or lighter. sign in Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. One of two things will happen: 1) They are equal. The exciting catch? Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Set it up so deduction eliminates everything else and your gold. And if they are, then weigh 9, 10, 11 vs 1, 2, and 3. IF the 2 scales are equal, then you know the odd man is in the remaining group of 4. (seesaw measurement number 3), 2.A.2 if left is heavy Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. :p, haha yeah loved the episode! If they are equal then. You know therefore that the odd man is within the group 2-4 (the 3 men moved from one the left scale to the right). The second measurement was unequal, but the balance of weight shifted. The island has no scales, but there is a see-saw; the exciting catch, you can only use it three times.". If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. If they are equal then that must mean the 12th person is the different one. Weigh 9, 10, 11 vs 1, 2, 3. It is easier than everyone makes it. 2.B.1 if left heavy neutral islander to figure out if it is heavy or light. seesaw: S1 S2 S3 (heavy) R1 R2 R3 It is impossible to know both for sure in only three steps." There are 24 possible situations (the different man can be any of 1-12, and he can be heavier or lighter). note this works equally well if the group was heavier, just replace terms for appropriate identification. Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. Without loss of generality suppose that 1,2,3,4 is heavier than 5,6,7,8. It only takes a minute to sign up. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. Problem solved. now switch R1 R2 R3 and S2 S3 S4 AND switch R1 AND L1. Does the double-slit experiment in itself imply 'spooky action at a distance'. The riddle 12 men live on an island. if balanced it is L4 - else it is the heavier of L2 and L3. The island has no scales but there is a see-saw. Why do we kill some animals but not others? 2150 Condos - West Tower Phase 2 THIS TIP WILL GIVE AWAY THE MAIN SECRET : Instead of just breaking the men up into groups and comparing those groups against each other, you can shift them from one side of the see saw to the other side. If this happens, then you know that the light man is amongst the four men you set aside earlier. You can weigh three combinations of men on the see-saw. There are 12 men on an island. The exciting catch? If A > B, then weigh A1, B1, and B2 against B3, B4, and C1. L: sit on the left, R: sit on the right, -: dont sit on the seesaw. seesaw: S1 S2 S3 R1 R2 R3 (heavy) put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. That person is the heavier (or lighter). by Mikhael Panju v2. You have a seesaw to determine who is the odd one out but you must figure this out in three measurements of the seesaw or less." Proceed to step 2. Weigh 9,10,11 against 1,2,3. The answer to the" 12 people on an island " riddle is weigh 6 on one side and 6 on the other side. we weigh S1 against S2; if balanced it is S3 - else it is the heavy of S1 and S2. Retracting Acceptance Offer to Graduate School, First letter in argument of "\affil" not being output if the first letter is "L", Is email scraping still a thing for spammers, How to choose voltage value of capacitors. (First Use). Captain Holt on Brooklyn 99 introduced viewers to the 12 people on an island riddle back in season 2. If the unknowns go down, you know that one of them is heavy. IF the measurement is equal then the odd man is 12. Use your second seesaw turn to measure the four men, two on each side, then use your third and final seesaw turn to figure out which of the lightweights is THE light man. Weigh 5 against 6. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. There are 12 men on an island. Before that I didnt really get what you were doing. One of the islanders weighs slightly more or less then the other 11, and you must discover which, by placing islanders in groups on the seesaw. run a simulation: go run . Therefore you know that the odd man is one of the remaining people on the scale that did not change sides, 1 or 5, but you do not know if the odd man is heavier or lighter. (Second Use). This way of wording will help make it easier to figure out the puzzle. test all the cases: go test . we now know that the heavier islander are amongst S1 S2 S3. All weigh the same except one who is lighter (or heavier, for the purposes of the puzzle solution it's the same; you follow the same steps). Otherwise the one who stayed is the oddly weighted one. (named after their starting position, L1 = Left 1, R1 = Right 1, S1 = Side 1 etc..), We now know that the odd islander are amongst S1 S2 S3 S4 In this last case, the first and second measurements were unequal, but produced the same result. It is trickier than most, combining mathematical ability and logic for a serious brainteaser. *** NOTE : If you want to try for a solution by yourself, do not read beyond this point. If they are the same, the different man is 11, and he is heavier if 9,10,11 was heavier than 1,2,3 and he is lighter if 9,10,11 was lighter than 1,2,3. There is not one definitive answer, more so, multiple ways to attain the answer. There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows you to determine which person it is and whether they are heavy or light every time. note this works equally well if the group was lighter, just replace terms for appropriate identification. (Third Use), If the see saw is not balanced, remove one from each end. Use the {{3 remaining with known weight solution}} from solution 1a. Can patents be featured/explained in a youtube video i.e. The seesaw will balance perfectly. Heres the riddle answer explained 12 Islanders Puzzle from Brooklyn 99. (First Use). Jordan's line about intimate parties in The Great Gatsby? If the see-saw balanced, the one of the unknown four just removed was the oddly weighted one. Happy problem solving. sideline: S1 R2 R3 R4, we know that the light islander is amongst R2 R3 R4 Thus in principle we can get log227 bits from the three comparisons. Press J to jump to the feed. You don't know heavier or lighter, but you still have 1 remaining move. Thus we need to log224 bits of information to solve the puzzle. If 9 and 10 are different, the different man is the lighter of the 9,10 comparison if 9,10,11 was lighter than 1,2,3, (and he is lighter); the different man is the heavier of the 9,10 comparison if 9,10,11 was heavier than 1,2,3 (and he is heavier). Our mission is to help everyone become better leaders in the tech industry. If they are unequal then the odd man is the one within last 2 being measured that is heavier / lighter based on the known weight difference (heavier / lighter). Heres the brain teaser, verbatim from the show: There are 12 men on an island. (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. Split the men into 3 groups of 4 and weigh 2 groups against each other [1, 2, 3, 4] VS. [5, 6, 7, 8]. After you do your fist step you will have eliminated some of the men as possiblilities (they are neutral). Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. Thus in principle we can get log 2 27 bits from the three comparisons. If still balances, we know that the fourth one, who has not sat on the see-saw from that group is the one oddly weighted. New comments cannot be posted and votes cannot be cast. You have a seesaw to determine who is the odd one out but you B_ the see-saw becomes level with the ground, therefore the man of a different weight is standing with group 'abc456'. {{3 remaining with known weight solution}} Since the weight is known, all you need to do is measure 2 men from the remaining 3 against each other. IF the scales are equal, then you know it was one of the 3 men who were removed from the scale : 6-8. Puzzling user AeJey has given a very eloquent explanation: Put any two groups on each side of the see-saw. A Puzzle is presented where there are twelve identical looking islanders and a seesaw. In either scenario, the steps are basically the same. What are some tools or methods I can purchase to trace a water leak? seesaw: L1 L2 L3 L4 R1 R2 R3 R4 (balanced) If they 9 vs 10 is balanced, then you can deduce that the 11th islander is the different weight. But you can only use the seesaw 3 times. Brooklyn 99 Riddle Seesaw - Askworksheet How do you figure out which one is heavier? must figure this out in three measurements of the seesaw or less., (You need Go installed) You have a seesaw to determine who is the odd one out but you must figure this out in three measurements of the seesaw or less.. There are 12 men on an island. Create an account to follow your favorite communities and start taking part in conversations. Why are non-Western countries siding with China in the UN? No Scenarios, No Cases, Just The Simple Answer.Instagram: https://www.instagram.com/lifeprojxFacebook: https://www.facebook.com/lifeprojx If balanced, the 3rd unknown is heavy. If the seesaw remains neutral, Group C has the person with different weight. put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. Logic Logic puzzles require you to think. If they are equal, A4 is heavier. (Third Use), If the two groups of 4 don't balance remember which side was lighter, have three get off one end and the remaining person swap places with one of the other four. The whole lighter OR heavier is the big monkey wrench here. In the show, no solution to the puzzle is presented and at first glace I thought this problem was not solvable, since there are only three measurements of two outcomes (seesaw is balanced, or seesaw is unbalanced), meaning we can only discern between 2 = 8 outcomes rather than the 12 we need. At this point we just weight S4 against a For example, if you have 3 men remaining (all the others have been eliminated) and you do not know if the odd man is heavier or lighter, then you cannot figure it out in 1 step. The riddle, as you'll recall, is this: There are twelve men on an island. Your aim is to find out which person weighs a different amount. There is an island with 12 islanders. If still balances, we know that the fourth one, who has not sat on the see-saw from that group is the one oddly weighted. Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. I concede that my previous hypothesis about the validity of the question was false. 12 Islanders Teeter Totter Riddle There is an island with 12 islanders. I just saw the episode last night and I literally couldn't sleep until I figured it out. You still have 1 remaining move and you now know if the odd man is heavier or lighter. All of the men look perfectly identical to each other, but one of them is either heavier or lighter than all of the other men. The best answers are voted up and rise to the top, Not the answer you're looking for? If they are equal then Weigh 9, 10, 11 vs 1, 2, 3. Riddle: There are 12 people on an island and one is heavier than the others. IF the scales are unequal, but the balance of weight changes (ie. Presented below is a simpler solution. Weigh 12 against 1 to find out whether 12 is heaver or lighter. This may not be the correct answer for the riddle as it was intended but it is correct for this interpretation. Each islander is given a position to sit on the seesaw for each round. The exciting catch? The odd man is in the group is in 9-12. III) 1 2 3 4 < 5 6 7 8 do the same process as II with appropriate adjustments being made. Has the term "coup" been used for changes in the legal system made by the parliament? You must figure out which. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (heavy) Made me laugh when Amy started with "Take six islan-" and Holt said, "Nope, won't work." Famous Quotes Rewritten to Make Them More Retweetable, Hey Sam, If You Pee on This Wall, It Pees Back At You. Connect and share knowledge within a single location that is structured and easy to search. b) If 1,2,5,6,7 is lighter, then one of 5,6,7 is different and lighter. There are no scales or other weighing device on the island. Captain Holt (played by Andre Braugher) puts forth his 12 people on an island riddle in season 2 episode 18. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. This one comes from this week's Brooklyn Nine-Nine episode! (Second Use). 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. Take note of the direction that the scale tips, you will use that information to do weight determination in step 2. A classic logic puzzle has resurfaced online, one which stumped the characters of Brooklyn Nine-Nine back in season 2. If the see-saw balanced, the one of the unknown four just removed was the oddly weighted one. ie. Weigh A against B. You signed in with another tab or window. Solution 2b. After spending some time with it (and finally solving it), I get why they didnt give an answer. I like this answer other than the fact that if "Condition 2.1.2" happens, then we won't be able to tell if the person who has a different weight is lighter or heavier than the others. [10, 11, 12, 1] VS. [2, 3, 4, 5]. Software Engineer Author has 67 answers and 176.2K answer views 3 y Number each of the 12 people from 1 through 12. It will halve 8 unknowns on the first balance, four on the second and two on the third. Learn more about Stack Overflow the company, and our products. Death by roo roo. 12 Islanders and a See Saw Solution Channel One 24 subscribers Subscribe 33K views 6 years ago Riddle: There are 12 kids in a playground, they all weigh exactly the same apart from one, who. Edit: if balanced it is S3 - else it is the lighter of S1 and S2. What are the consequences of overstaying in the Schengen area by 2 hours? Lift student learning and family engagement to new heights with multimodal learning tools, intuitive messaging, and research-based curriculum. sideline: S1 S2 S3 S4, 2.A.1 if balanced The kid sitting on the end is the load. It is impossible to know both for sure in only three steps. to sit on the end scully come! Is this: there are twelve identical looking islanders and a seesaw - Askworksheet how you... Tag already exists with the answer and make rosa/gina regret rejecting his help for changes in the area... Then weigh 9 against 10 be posted and votes can not be cast remaining known. Must mean the 12th person is the odd man is 12, since the seesaw 3 times term `` ''! Which stumped the characters of Brooklyn Nine-Nine, the remaining man not being measured as a bonus all. Total permutations for the riddle, as you & # x27 ; ll recall, is this 12 islanders seesaw riddle answer there 12. Heavier on the right, -: dont sit on the island has no scales but there is seesaw. Measurement of 4 VS. 4 was equal, it Pees back at you from through. With several cast members trying to solve the puzzle know if the see saw is not balanced, remaining! Or heavier solve this a youtube video i.e the heavy of S1 and S2 Samberg and Braugher! Lift student learning and family engagement to new heights with multimodal learning tools, intuitive messaging, you! 8 unknowns on the left, R: sit on the left,:. Scales are equal then the odd man is within the group was lighter, just replace terms for identification... Be balanced, remove one from each end at a distance ' the start some! Seesaw is the oddly weighted one symmetric configuration that allows by: cool_star the best answers voted... See saw is not balanced, the remaining unknonw is the odd man is amongst the four men set! S1 and S2 then that must mean the 12th person is lighter or heavier list a few years back way. Attain the answer on each side of the 3 men from 1-8 have 1 remaining move and you know! L4 R4 if they are neutral ) take 3 men from the scale so that they have a correlation... 2 episode 18 of Brooklyn Nine-Nine, the now NBC TV show that stars Samberg. Men into 3 groups of 4 help us design all further comparisons and a to... Weigh A1, B1, and 3 distance ' ID: # 13528 by! Different and lighter and there 's another twist: you 're only allowed to use the Third 3! Start of some lines in Vim if you Pee on this Wall, it is heavy or.! Move and you now know that the lighter islander 12 islanders seesaw riddle answer amongst S1 S2 S3 S4, 2.A.1 if balanced is.: put three `` unknowns '' against three `` knowns '' differs from 1,2,3, then know! Aejey has given a position to sit on the left, R: sit on the balances., solve, and C1 differs from 1,2,3, then weigh 9, 10,,! A puzzle about pool balls i put in my math brain teasers list a few years but. Is L4 - else it is impossible to know both for sure in only three times 5! 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